Binaire puzzel van 21 december 2013
1
1
1
1
1
0
1
1
1
0
0
0
1
0
1
1
0
1
0
0
0
1
0
0
1
1
0
1
0
1
1
0
1
0
1
0
1
0
0
1
0
0
1
1
1
1
0
0
1
1
0
0
0
1
1
0
0
1
1
0
0
0
1
1
0
0
1
1
1
0
0
1
1
0
0
1